Practice 1
From 11:45 a.m. to 12:20 p.m. on the same day, how many minutes pass?
Answer and teaching response
35 · Fifteen minutes reach noon and twenty more reach 12:20.
Use forward jumps to connect two clock times and explain why an hour changes after sixty minutes.
Get the student and teacher materialsLearning goal: A learner can calculate a same-day time interval in minutes and check it by adding the interval to the starting time.
You will need: Pencil, paper and an optional demonstration clock. All times in this workshop are on the same morning or afternoon unless stated otherwise.
A reading session starts at 9:35 a.m. and ends at 10:10 a.m. How long does it last?
35 minutes: 25 minutes from 9:35 to 10:00, then 10 more minutes to 10:10.
A learner might say: Subtract 9.35 from 10.10 as if the clock readings were decimal numbers.
The digits after the colon count minutes, and 60 minutes make an hour. A decimal subtraction would use groups of one hundred, so it would describe a different system.
Use the first three tasks for guided practice. Try the final task without help. Record a drawing or equation as well as the answer.
From 11:45 a.m. to 12:20 p.m. on the same day, how many minutes pass?
35 · Fifteen minutes reach noon and twenty more reach 12:20.
A session runs from 2:18 p.m. to 2:52 p.m. How many minutes does it last?
34 · Both readings are in the same hour, so subtract the minute counts.
A workshop runs from 10:50 a.m. to 11:15 a.m. Find its duration in minutes.
25 · Ten minutes reach 11:00, followed by fifteen more.
A walk begins at 3:47 p.m. and ends at 4:26 p.m. How many minutes pass? Draw jumps to support your answer.
39 · Thirteen minutes reach 4:00 and twenty-six more reach 4:26.
A task starts at 1:50 p.m. and lasts 25 minutes. What time does it finish, and how can you check?
It finishes at 2:15 p.m. Ten minutes reach 2:00 and the remaining fifteen reach 2:15. Counting back confirms the 25-minute interval.
Look for:
If the idea is not secure: Draw the next whole hour first, then fill in the minutes needed to reach it.
If the learner is ready: Solve the same interval using one large jump followed by a correction, and explain why it agrees with the split jumps.
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